27. Remove Element | Two Pointer Approach Explained in C++ | LeetCode Solution

In this video, I solve LeetCode 27: Remove Element using an efficient Two Pointer approach in C++. ✅ Problem Explanation ✅ Optimized Approach ✅ Dry Run ✅ Time & Space Complexity ✅ Clean C++ STL-Based Code Approach: We use a pointer `k` to keep track of the position where non-target elements should be placed. While traversing the array, every element not equal to `val` is copied to the front of the array. Algorithm: 1. Initialize pointer `k = 0` 2. Traverse the array 3. If current element is not equal to `val` 4. Place element at index `k` 5. Increment `k` 6. Return `k` as the new length Time Complexity: O(N) Space Complexity: O(1) 🔗 GitHub: https://github.com/atulXdev 🔗 LeetCode Profile: https://leetcode.com/u/atul_singh_cg/ 🔗 LinkedIn: https://www.linkedin.com/in/atul-singh-987b0b394/ #leetcode #dsa #cpp #removeelement #twopointer #codinginterview #striverdsa #leetcode27 #datastructures #algorithms