Back to Browse

#4 Java Leet Code✅ - Finding Shortest Path - Tamil | Step by Step | DinaTechy #coding #leetcodejava

172 views
Nov 2, 2024
17:06

The problem: 1. Given two words (start and end), and a dictionary, find the length of the shortest transformation sequence from start to end. 2. Only one letter can be changed at a time, each intermediate word must exist in the dictionary. Example: start = "hit" - "ait" - "bit" - "dot" = 1 end = "cog" dictionary = ["hot","dot","dog","lot","log"] Note: Shortest Path is '5'. Steps to Approach: 1. Check the end word is in the Dictionary, if not return 0. Add the end word to the dictionary. 2. Treat each word as a node and an edge exists between two nodes if they differ by exactly one letter. 3. Use a queue to track the current word and the number of transformations needed. 4. Use a set to keep track of visited words. 5. If we reach the end word, return the transformation count. 6. If we exhaust the queue without finding the end word, return 0 (meaning no transformation sequence exists). Time Complexity: The time complexity is O(N×M2)O(N \times M^2)O(N×M2): • NNN is the number of words in the dictionary. • MMM is the length of each word, as we iterate over each character to create transformations. Telegram - https://t.me/+lhWGhenJ5tw0NDk1 #codingtamilan #codingintamil #java #javainterviewquestionsandanswers #javainterviewquestionsandanswersforfreshers #javainstitute #javaprogramming#leetcodedailychallenge #leet_preparation_tips #javainterviewquestionsandanswersforexperienced #dynamicprogramming #dynamicprogram #dynamic #1000subscriber #100dayschallenge #100daystransformation #100daysofcode #100days #zohorecruitment #zohospecialist #zoholatestprogramming #zohotutorial #zohojobs #javaleetcode #leetcodejava #leetcodeproblems

Download

1 formats

Video Formats

360pmp422.7 MB

Right-click 'Download' and select 'Save Link As' if the file opens in a new tab.

#4 Java Leet Code✅ - Finding Shortest Path - Tamil | Step by Step | DinaTechy #coding #leetcodejava | NatokHD