Boost converter working

Boost converter is a DC to DC converter Output voltage is greater than input voltage Hence it is a step up converter During switch on inductor will get charged at that time load get supply from capacitor. Capacitor voltage will not go to source side due to the presence of diode. Diode will be reverse biased During switch off inductor will discharge so both voltage source and inductor will act as a source and will deliver power to the load. At this time capacitor will get charged Capacitor is parallel to load therefore both will have same voltage because element connected in parallel have same voltage. Apply KVL to get inductor voltage Apply KCL to get capacitor current Vo is greater than Vs output voltage equation is obtained from volt-sec balance equation of inductor. Average voltage across an inductor in DC- steady state will be zero. output current equation is obtained from Amp-sec balance equation of capacitor Average current in capacitor will be zero.