The triangle midsegment theorem has two important ideas: 1. the midsegment is parallel to a side of the triangle; 2. the midsegment is always half the length of this side. , i.e., If DF is a midsegment of ∆ABC, then DF∥AC and DF = 1/2 AC = AE = EC (E is the midpoint of AC). From this understanding, when the three midsegments are drawn to form a "midsegment triangle", a lot of properties and shapes emerge. In this video, these properties and shapes are highlighted and some of them are used to prove that the midsegment triangle is similar to the original triangle, watch on!
