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Haskell 3 : Types and typeclasses

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Jan 27, 2015
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Haskell 3 : Types and typeclasses Unlike Java or Pascal, Haskell has type inference. If we write a number, we don't have to tell Haskell it's a number. It can infer that on its own, so we don't have to explicitly write out the types of our functions and expressions to get things done. We covered some of the basics of Haskell with only a very superficial glance at types. However, understanding the type system is a very important part of learning Haskell. A type is a kind of label that every expression has. It tells us in which category of things that expression fits. The expression True is a boolean, "hello" is a string, etc. Now we'll use GHCI to examine the types of some expressions. We'll do that by using the :t command which, followed by any valid expression, tells us its type. Let's give it a whirl. ghci> :t 'a' 'a' :: Char ghci> :t True True :: Bool ghci> :t "HELLO!" "HELLO!" :: [Char] ghci> :t (True, 'a') (True, 'a') :: (Bool, Char) ghci> :t 4 == 5 4 == 5 :: Bool bomb Here we see that doing :t on an expression prints out the expression followed by :: and its type. :: is read as "has type of". Explicit types are always denoted with the first letter in capital case. 'a', as it would seem, has a type of Char. It's not hard to conclude that it stands for character. True is of a Bool type. That makes sense. But what's this? Examining the type of "HELLO!" yields a [Char]. The square brackets denote a list. So we read that as it being a list of characters. Unlike lists, each tuple length has its own type. So the expression of (True, 'a') has a type of (Bool, Char), whereas an expression such as ('a','b','c') would have the type of (Char, Char, Char). 4 == 5 will always return False, so its type is Bool. Functions also have types. When writing our own functions, we can choose to give them an explicit type declaration. This is generally considered to be good practice except when writing very short functions. From here on, we'll give all the functions that we make type declarations. Remember the list comprehension we made previously that filters a string so that only caps remain? Here's how it looks like with a type declaration. removeNonUppercase :: [Char] -> [Char] removeNonUppercase st = [ c | c <- st, c `elem` ['A'..'Z']] removeNonUppercase has a type of [Char] -> [Char], meaning that it maps from a string to a string. That's because it takes one string as a parameter and returns another as a result. The [Char] type is synonymous with String so it's clearer if we write removeNonUppercase :: String -> String. We didn't have to give this function a type declaration because the compiler can infer by itself that it's a function from a string to a string but we did anyway. But how do we write out the type of a function that takes several parameters? Here's a simple function that takes three integers and adds them together:

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