LeetCode 110 | Balanced Binary Tree | Daily LeetCode | Day 39/365 | DFS + Height Optimization | C++

LeetCode 110 | Balanced Binary Tree | Daily LeetCode | Day 39/365 | DFS + Height Optimization | C++ Solution In this video, we solve LeetCode 110: Balanced Binary Tree, where the task is to check whether a binary tree is height-balanced — meaning the height difference between left and right subtrees of every node is at most 1. 🧠 Core Idea: We use a DFS-based approach that: • Computes the height of subtrees • Detects imbalance early using a sentinel value (-1) • Avoids recomputing heights (optimized recursion) 📌 What you’ll learn in this video: • What a height-balanced binary tree is • Naive vs optimized recursive approach • How DFS helps reduce time complexity • Early stopping when imbalance is found • Clean and interview-ready C++ implementation • Time and space complexity analysis ⏱ Time Complexity: O(n) 💾 Space Complexity: O(h) (recursive stack, where h is tree height) 💻 Problem Link: https://leetcode.com/problems/balanced-binary-tree/ 🎯 Why this problem matters: This is a must-know binary tree problem asked in coding interviews, helping you master tree traversal, recursion, and optimization techniques. 👍 Like the video if recursion finally made sense 💬 Comment if you want a dry run on a sample tree 🔔 Subscribe for the 365 Days of LeetCode Challenge #LeetCode #DailyLeetCode #Day39of365 #BinaryTree #DFS #Recursion #CPlusPlus #DSA #InterviewPreparation