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LeetCode 1365 Solution in Python | Brute Force to Optimal Hashing Explained | EDREALM @Edrealm-k

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May 12, 2026
18:38

In this video, we solve LeetCode 1365 - How Many Numbers Are Smaller Than the Current Number using both the Brute Force Approach and the Optimal Hashing Approach in Python with detailed explanation, dry run, coding, and time complexity analysis. This is an important DSA interview question frequently asked in companies like Google, TCS, Infosys, Oracle, HCL, and Accenture. If you are preparing for: ✅ Coding Interviews ✅ DSA & LeetCode Preparation ✅ Product & Service Based Companies ✅ Python Interview Questions ✅ Placement Preparation ✅ Competitive Programming then this video will help you understand the problem from basics to optimal solution. 📌 What You’ll Learn: Problem Understanding Brute Force Approach Optimal Hashing Technique Step-by-Step Dry Run Python Coding Implementation Time Complexity & Space Complexity Analysis ⏱️ Timestamps: 00:00 - Introduction 00:22 - Question Explanation 01:18 - Approach 1: Brute Force 03:36 - Code for Brute Force Approach 06:40 - Approach 2: Hashing (Optimal) 12:43 - Code for Hashing Approach 16:46 - Time Complexity Explanation 🔥 Subscribe to EDREALM for: LeetCode Solutions DSA Tutorials Coding Interview Questions Python Programming Placement Preparation Competitive Programming 📚 Keywords: LeetCode 1365, How Many Numbers Are Smaller Than the Current Number, LeetCode Python Solution, Hashing Technique in Python, Brute Force vs Optimal Solution, DSA in Python, Coding Interview Questions, LeetCode for Beginners, Python Problem Solving, Placement Preparation, Competitive Programming, EDREALM Coding #leetcode #leetcode1365 #python #dsa #hashing #codinginterview #competitiveprogramming #placements #pythoncoding #programming #edrealm

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LeetCode 1365 Solution in Python | Brute Force to Optimal Hashing Explained | EDREALM @Edrealm-k | NatokHD