LeetCode 167 Two Sum II Solution | Two Pointers Technique | Infotechiezz

🔢 Master LeetCode 167 Solution | Two Sum II - Input Array Is Sorted | Live Coding Tutorial Welcome to Infotechiezz! In this comprehensive live session, we break down LeetCode Problem 167 – "Two Sum II - Input Array Is Sorted". This is a classic Array and Two Pointers challenge frequently asked in TCS NQT, Ninja, Prime, and FAANG interviews. Whether you're a beginner struggling with array logic or an experienced coder preparing for off-campus placements, this step-by-step guide will help you understand, implement, and optimize the Two Sum solution with confidence. ✅ What You'll Learn in This Video/Blog (Detailed Timestamps): 🔹 0:00 – Introduction: Welcome to Infotechiezz. Overview of the session and why LeetCode 167 is critical for array manipulation interviews and coding rounds. 🔹 0:51 – Problem Explanation: Deep dive into the problem requirements – finding two numbers in a sorted array that add up to a specific target. Understanding 1-based indexing and constraints. 🔹 2:40 – Pseudo Code Explain: Step-by-step logical flow before coding. Understanding the Two Pointers approach (Left vs Right) vs Hash Map approach for sorted arrays. 🔹 6:53 – Coding Part: Complete working code implementation in C++, Java, and Python. Clean syntax, variable naming, and handling the return format correctly. 🔹 8:59 – Outro & Next Steps: Summary of key takeaways, how to access resources, and what to watch next on Infotechiezz for more DSA problems. 🎯 Why This Matters for Placement Aspirants: LeetCode 167 tests core DSA fundamentals – Array Traversal, Two Pointers Pattern, and Search Optimization – all critical for Product-Based company coding sections. Mastering this pattern helps you solve similar problems like 3Sum, Container With Most Water, and Valid Palindrome II. Companies like Amazon, Microsoft, Google, and TCS Prime often ask variations of the Two Sum problem family. 💡 Pro Tips for Exam Success: ✔️ Always handle edge cases: No solution found (though problem guarantees one), duplicate numbers, and negative targets. ✔️ Use Optimized Logic: Since the array is sorted, use Two Pointers (O(n)) instead of Hash Map (O(n) space) to achieve O(1) space complexity. ✔️ Practice writing clean, commented code – Interviewers value readability and logical flow over clever one-liners. ✔️ Memorize the complexity justification – often asked to test optimization knowledge (Why Two Pointers works on sorted arrays). ✔️ Remember 1-based indexing: LeetCode 167 requires returning indices starting from 1, not 0. 📚 Resources Mentioned: • Free LeetCode 167 Code Template (GitHub Link in Description) • Two Pointers Cheat Sheet (PDF Download) • Top 50 Array Problems for Placements (Google Drive) • Infotechiezz Discord Community for Doubt Solving 🔔 Don't Forget to: ✅ Like this video if it helped you ✅ Subscribe to @infotechiezz for daily coding content ✅ Hit the bell icon for instant updates on LeetCode & Placement series ✅ Share with friends preparing for off-campus drives leetcode 167 solution, two sum ii input array is sorted, leetcode 167 explained, leetcode 167 python, leetcode 167 java, leetcode 167 c++, leetcode contest solution, product based company coding questions, off campus placement preparation, faang interview preparation, dsa problems solved, two pointers technique, sorted array search, binary search vs two pointers, optimized coding solution #LeetCode167 #LeetCodeSolution #CodingInterview #PlacementPreparation #OffCampus #CPlusPlus #JavaProgramming #PythonCoding #AlgorithmDesign #DryRun #ComplexityAnalysis #DSA #Optimization #CompetitiveProgramming #Infotechiezz #CodingTutorial #FAANG #TechJobs #CodingQuestions #ProgrammingLogic #CodeWithInfotechiezz #TechEducation #LearnToCode #CodingForBeginners 📲 CONNECT WITH INFOTECHIEZZ: 📩 Email: [email protected] 📸 Instagram: https://www.instagram.com/infotechiezz/ 💼 LinkedIn: https://www.linkedin.com/in/infotechiezz/ ▶️ YouTube: https://www.youtube.com/@InfoTechiezz 💬 WhatsApp Channel: https://www.whatsapp.com/channel/0029Vb7QJZG8fewpER7N8U0V 🐦 X (Twitter): https://x.com/infotechiezz 🔢 Quick Problem Logic: Since the array is sorted, use Two Pointers: 1. Initialize left = 0, right = n-1. 2. Calculate sum = nums[left] + nums[right]. 3. If sum == target, return indices. 4. If sum target, move left pointer forward. 5. If sum target, move right pointer backward. Edge Case: Remember to return 1-based indices (index + 1). ❓ Frequently Asked Questions (FAQ): Q1: Is this problem good for beginners? A1: Yes, it's considered Easy/Medium and is perfect for learning the Two Pointers pattern. Q2: What is the best language for this? A2: Python for readability, C++ for speed in competitive contests with large constraints. Q3: How often does this pattern appear? A3: Extremely frequently. It's the foundation for 3Sum, 4Sum, and many sliding window problems. Thanks for watching! Keep coding, keep learning, and stay tuned to Infotechiezz for more placement-focused tutorials. 🚀💻✨