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LeetCode 1758 | Minimum Changes to Make Alternating Binary String | Python | AlgoYogi

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Oct 12, 2025
17:27

Welcome to AlgoYogi! πŸš€ Start Your Smart Coding Prep at πŸ‘‰ https://algoyogi.io We solve LeetCode 1758: Minimum Changes to Make Alternating Binary String using a one-pass mismatch counter. Goal: given a binary string s, return the minimum number of flips to make it alternating. Approach: - Compare s against two target patterns: β€’ Pattern A: starts with '0' β†’ "010101..." β€’ Pattern B: starts with '1' β†’ "101010..." - In one pass, count mismatches for both patterns. - Answer = min(mismatches for A, mismatches for B). πŸ‘‰ Problem Link: https://leetcode.com/problems/minimum-changes-to-make-alternating-binary-string/ --- ### ⏱ Timestamps 0:00 Introduction 0:20 Problem Statement 1:30 One-Pass Dual Pattern Check 12:00 Python Code Walkthrough 17:00 Time & Space Complexity --- ### πŸ’‘ Why Watch? - Elegant O(n) scan with O(1) space - Works directly on the string without building new arrays - Interview-friendly trick: evaluate both alternating targets at once #LeetCode #AlternatingBinaryString #Python #AlgoYogi #String #Greedy

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LeetCode 1758 | Minimum Changes to Make Alternating Binary String | Python | AlgoYogi | NatokHD