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LeetCode 1913 | Max Product Difference Between Two Pairs | Python Sort or Scan | AlgoYogi

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Oct 8, 2025
13:54

Welcome to AlgoYogi! 🚀 Start Your Smart Coding Prep at 👉 https://algoyogi.io In this video, we solve **LeetCode 1913: Maximum Product Difference Between Two Pairs** using Python. We need to pick two disjoint pairs (a, b) and (c, d) from the list such that the product difference `(a * b) − (c * d)` is maximized. Approaches: 1) **Sorting**: sort the array and pick the two largest values for the first pair, and two smallest for the second pair. 2) **Single-pass scanning**: track two largest and two smallest values in one traversal, then compute. 👉 Problem Link: https://leetcode.com/problems/maximum-product-difference-between-two-pairs/description/ --- ### ⏱ Timestamps 0:00 Introduction 0:20 Problem Statement 1:10 Sort Approach Explanation 8:30 Python Code Walkthrough 13:30 Time & Space Complexity --- ### 💡 Why Watch? - Learn array value tracking patterns (maxima and minima in one pass) - Avoid full sorting if only extreme values matter - Interview-friendly pattern for combining pair products #LeetCode #MaxProductDifference #Python #AlgoYogi #ArrayPatterns

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LeetCode 1913 | Max Product Difference Between Two Pairs | Python Sort or Scan | AlgoYogi | NatokHD