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In this video, we solve **LeetCode 217: Contains Duplicate** using Python. Problem: given an integer array nums, return true if any value appears more than once in the array; otherwise return false.
We cover two methods:
- Use a set to track seen numbers and check duplicates in one pass
- Sort the array and check consecutive elements for equality
👉 Problem Link: https://leetcode.com/problems/contains-duplicate/
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### ⏱ Timestamps
0:00 Introduction
0:20 Problem Statement
0:30 Set-Based One-Pass Method
5:00 Python Code Walkthrough
6:30 Time & Space Complexity
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### Why Watch?
- Learn fast detection of duplicates with O(n) time using a hash set
- Compare with sorting method: O(n log n) time, but simple logic
- Understand trade-offs: memory vs performance
#LeetCode #ContainsDuplicate #Python #HashSet #Sorting #AlgoYogi
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LeetCode 217 | Contains Duplicate | Python Set vs Sorting Methods | AlgoYogi | NatokHD