LeetCode 268 | Missing Number | Easy Problem | C++ Solution

In this video, I explain the problem step-by-step, discuss the optimal approach, and implement the solution live while coding. 🚀 Problem: LeetCode 268 – Missing Number Find the missing number from an array containing distinct numbers in the range [0, n]. 🧠 Approach: Calculate the expected sum of numbers from 0 to n using the formula: n * (n + 1) / 2 Traverse the array and calculate the actual sum Subtract the actual sum from the expected sum The remaining value is the missing number ⏱ Time Complexity: O(n) 📦 Space Complexity: O(1) 🔗 GitHub Repository: https://github.com/VishwaPatel892/Leetcode_Solutions 👨‍💻 LeetCode Profile: https://leetcode.com/u/vishwa0102/ 💼 LinkedIn: https://www.linkedin.com/in/vishwa-patel-9bab9639a 📝 Notes: Based on mathematical summation formula Efficient single-pass solution No extra space required Alternative approaches include XOR and sorting #leetcode #leetcode268 #dsa #algorithms #coding #programming #codinginterview #interviewprep #arrays #math #leetcodeeasy #problemSolving #learncoding #codewithme #developerlife #tech #placements #softwareengineer #codinglife #100daysofcode 👍 Like | Comment | Subscribe for more LeetCode solutions!