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We solve LeetCode 383: Ransom Note using Python and a simple frequency counting approach.
Goal: return true if the ransom note can be constructed from the magazine letters, otherwise false. Each letter in the magazine can be used only once.
Approach:
- Count letters in magazine using a Counter or a fixed 26-length array
- For each character in ransom note, check that its count in magazine is still positive; decrement as you use it
- If any letter is missing or exhausted, return false; otherwise true
👉 Problem Link: https://leetcode.com/problems/ransom-note/description/
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### ⏱ Timestamps
0:00 Introduction
0:20 Problem Statement
0:30 Counting Approach
6:00 Python Code Walkthrough
8:15 Time and Space Complexity
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### 💡 Why Watch?
- Clean O(n) solution with straightforward counting
- Works efficiently with either Counter or fixed array for lowercase letters
- Interview staple: resource checking with decrements
#LeetCode #RansomNote #Python #AlgoYogi #Counting #HashMap
