LeetCode 605 | Can Place Flowers | Python Greedy Two-Pointer | AlgoYogi

Welcome to AlgoYogi! 🚀 Start Your Smart Coding Prep at 👉 https://algoyogi.io In this video, we solve **LeetCode 605: Can Place Flowers** using Python and a clear, **greedy one-pass** technique with two pointers. You are given a flowerbed represented by an array where 0 means empty and 1 means planted. You need to determine if you can plant n new flowers without violating the rule that no two flowers are adjacent. Approach: - Traverse the array once - For each plot that is empty, check if both neighbors (or boundary) are empty or out of range - If so, plant a flower (set to 1) and decrement n - Early exit if n reaches 0 Example: - flowerbed = [1,0,0,0,1], n = 1 → true (plant at index 2) - flowerbed = [1,0,0,0,1], n = 2 → false --- ### ⏱ Timestamps 0:00 Introduction 0:20 Problem Statement 0:55 Greedy Two-Pointer Approach 5:40 Python Code Walkthrough 8:46 Time & Space Complexity --- ### Why Watch? - Learn an intuitive greedy method for a classic array problem - Uses boundary-aware checks to avoid out-of-range errors - Clean, efficient solution with O(n) time and O(1) space complexity #LeetCode #CanPlaceFlowers #Python #AlgoYogi #Greedy #TwoPointers