LeetCode Daily | Construct Minimum Bitwise Array I (3314) | Bitwise OR Logic | C++

In today’s LeetCode Daily Challenge (Day 20), we solve 3314. Construct the Minimum Bitwise Array I using a bitwise OR–based brute-force approach. Problem link: https://leetcode.com/problems/construct-the-minimum-bitwise-array-i/description/?envType=daily-question&envId=2026-01-20 Solution: https://leetcode.com/problems/construct-the-minimum-bitwise-array-i/solutions/7510108/this-or-condition-hides-a-simple-trick-b-pplb The goal is to construct an array ans such that: ans[i] | (ans[i] + 1) == nums[i] and ans[i] is as small as possible. This problem helps build intuition around bitwise OR behavior, especially how consecutive numbers interact at the binary level. 🔍 What’s covered in this video: ✅ Understanding the bitwise OR condition ✅ Why checking x | (x + 1) works ✅ Handling cases where no valid value exists ✅ Clean brute-force implementation in C++ ✅ Time and space complexity analysis 📊 Complexity: Time Complexity: O(n × m) Space Complexity: O(1) 📌 A great problem to strengthen bitwise fundamentals, often tested in interviews. 🔔 Subscribe to The Boolean Brain for daily LeetCode solutions and interview prep. 📧 Email: [email protected] 📸 Instagram: https://www.instagram.com/thebooleanbrain/