LeetCode Problem 443: String Compression | Two-Pointer C# Solution Explained

Here's my solution to the LeetCode Problem 443: String Compression, implemented in C# using a Two-Pointer Approach. 🚀 💡 Problem Overview: The goal is to compress a character array in place by replacing sequences of repeating characters with the character followed by the count of repetitions. This solution keeps track of a previous character and its count, then compresses the sequence directly into the original array using a two-pointer technique. ✅ What You'll Learn in This Video: How to solve string compression problems efficiently using two pointers. Techniques to write an in-place algorithm for modifying character arrays. A clear breakdown of the logic for grouping and compressing repeated characters. 🔔 Code Highlights: Time Complexity: O(n), where n is the number of characters in the array. Each character is processed once to compress the string in-place. Space Complexity: O(1) (excluding input/output), as no extra space is used for the compression. Core Insight: This solution uses an index pointer to place the compressed characters back into the same array and iteratively writes the count of each character only when it is greater than one. 💡 This problem is a great exercise for in-place array manipulations and is commonly featured in coding interviews to test low-level string and pointer handling skills. 🎥 If you enjoyed this solution, don’t forget to Like, Subscribe, and Share for more insights into efficient algorithms, interview preparation strategies, and LeetCode explanations! ✨ #LeetCode #StringCompression #TwoPointerTechnique #CSharp #ProblemSolving #EfficientAlgorithms #CodingInterview #Strings