Paths of 0-1 Knapsack Problem Dynamic Programming | 01 Knapsack

Please consume this content on nados.pepcoding.com for a richer experience. It is necessary to solve the questions while watching videos, nados.pepcoding.com enables that. NADOS also enables doubt support, career opportunities and contests besides free of charge content for learning. In this video, we discuss the Paths of 01 Knapsack Problem using dynamic programming. In this problem, 1. You are given a number n, representing the count of items. 2. You are given n numbers, representing the values of n items. 3. You are given n numbers, representing the weights of n items. 3. You are given a number "cap", which is the capacity of a bag you've. 4. You are required to calculate and print the maximum value that can be created in the bag without overflowing it's capacity. 5. Also, you have to print the indices of items that should be selected to make maximum profit. 6. You have to print all such configurations. Note - Each item can be taken 0 or 1 number of times. You are not allowed to put the same item again and again. To submit this question, click here: https://www.pepcoding.com/resources/data-structures-and-algorithms-in-java-levelup/dynamic-programming/zero-one-knapsack-re-official/ojquestion For a better experience and more exercises, VISIT: https://www.pepcoding.com/resources/online-java-foundation Have a look at our result: https://www.pepcoding.com/placements Follow us on our FB page: https://www.facebook.com/pepcoding Follow us on Instagram: https://www.instagram.com/pepcoding Follow us on LinkedIn: https://www.linkedin.com/company/pepcoding-education