Pattern 4-Binary Search - Leetcode 852 - Interview Problems | Data Structures #leetcode #interview

leetcode 852 - Bitonic Array or Mountain Array explained in tamil. Links: DSA in Tamil - https://youtube.com/playlist?list=PLEiGLqoe9pw4UWhtVpKaAvQojVlfZO2f5&si=bx1OiwWu0gjzKCLF Binary Search in Tamil - https://youtu.be/um64-3hynis?si=IAXeIDgdx51Y-UiL DSA in Tamil - https://youtube.com/playlist?list=PLEiGLqoe9pw4UWhtVpKaAvQojVlfZO2f5&si=bx1OiwWu0gjzKCLF Binary Search in Tamil - https://youtu.be/um64-3hynis?si=IAXeIDgdx51Y-UiL Binary Search Problems Pattern 1 ( https://youtu.be/TaH03Tl0L9k?si=cpaSJgCjvE3xMqVA) Binary Search Problems Pattern 2 ( https://youtu.be/x_Ric7JqAgk?si=3wkMgc6Ibshjm852 ) Binary Search Pattern 3 - https://youtu.be/yv3lMUAZeHI Binary Search Pattern 4 (problem 1) MOUNTAIN ARRAY PROBLEM - https://youtu.be/35GrtErYoxs Binary Search Pattern 4 (problem 2)- https://youtu.be/sPwCuFXRfEw?si=DBtpsysp8Et6vxnZ Pattern 5 - https://youtu.be/nTRMiaaDz5w pattern 6, 7, 8 will be out soon Chapters 00:00 Problem Statement 01:11 Approaching the Problem 04:04 Pseudo-code Explained 08:46 Example-skip to here if you're on time crunch 12:09 Code 15:04 Rant and Advice 17:27 Bug Fixing 18:06 Next Problem Pattern explained LeetCode problem 852, titled "Peak Index in a Mountain Array," involves finding the peak element in an array. A peak element is defined as an element that is greater than its neighbors. The problem is often solved using a binary search algorithm. Here's an explanation of how to approach this problem using the start, end, and mid pointers in a binary search: Initialize Pointers: start points to the beginning of the array, typically index 0. end points to the end of the array, typically index n - 1, where n is the length of the array. Binary Search: While start is less than end, calculate the mid index as (start + end) / 2. Compare mid element with its neighbors: Compare the element at index mid with its adjacent elements, i.e., elements at indices mid - 1 and mid + 1. Decide Search Space: If the element at index mid is greater than both of its neighbors, it is a peak, and you can return mid. If the element at index mid is less than its right neighbor, it means the peak is on the right side of mid, so set start = mid + 1. If the element at index mid is less than its left neighbor, it means the peak is on the left side of mid, so set end = mid - 1. Repeat the Binary Search: Repeat steps 2-4 until start becomes greater than or equal to end. Return the Peak Index: Return start or end as the peak index, as they will converge to the peak element. Keywords: Binary Search, Data Structures, Algorithms, Python, Interview Questions, Coding, LeetCode, Tamil, Binary Search in Tamil, Data Structures in Tamil, Algorithms in Tamil, Python Programming in Tamil, Interview Questions in Tamil, Coding in Tamil, LeetCode in Tamil.