C Program | Newton's Backward Interpolation
https://drive.google.com/file/d/1sKYxXiAAzwCWE_B4LWC8IC4BYauqVv8p/view?usp=drive_link
pdf:
https://drive.google.com/file/d/1Rv4j0IDvrSDtmw2IU3v083ChRSfsn9Er/view?usp=drive_link
All videos of Numerical Practicals:
https://youtube.com/playlist?list=PLIxKJOW5qKqoxmRh0oJFEMFvpQLnoIuy9&si=Dv7IHzKLcF3KfmXW
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#Semester-6 (CBCS)
# B.Sc.(Honours) Mathematics,
# University of Calcutta
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P16:Newton's Backward / DATE: 08/04/2024
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Ans: / 22B1Q1P2
R=0: ..........f(1.41)=1.7297237842
R=1:.......... f(1.42)=1.7338974458
R=2:........... f(1.43)=1.7380811780
R=3: ..........f(1.44)=1.7422750052
R=4: ..........f(1.45)=1.7464789517
R=5: .......... f(1.46)=1.7506930419
R=6: .......... f(1.47)=1.7549173003
R=7: ..........f(1.48)=1.7591517514
R=8: .........f(1.49)=1.7633964199
R=9: ........f(1.50)=1.7676513304
