Product of Array Except Self | LC 238 | Java | Time & Space | Tamil

In this video, we will go over the Product of Array Except Self problem (LeetCode problem) in Tamil. The goal is to compute the product of all the elements in an array, except for the element at the current index, for each index in the array. Problem Overview: Given an integer array nums, return an array output such that output[i] is equal to the product of all the numbers in nums except nums[i]. The key challenge is to solve this problem without using division and with optimal time and space complexity. Key Insights: We can break the problem into two parts: Prefix product: For each element in the array, calculate the product of all the elements before it. Suffix product: For each element in the array, calculate the product of all the elements after it. By combining the results of the prefix and suffix products, we can obtain the desired result for each index in the array. Approach: Prefix product: We compute the product of all elements to the left of the current element. Suffix product: We compute the product of all elements to the right of the current element. Final result: Multiply the prefix and suffix products together to get the final result for each element. Time Complexity: The solution runs in O(n) time where n is the length of the input array, because we go through the array a constant number of times. Space Complexity: The space complexity is O(n) because we use an additional output array to store the results. Edge Cases: Arrays with zeros: How do we handle arrays containing zeros? The solution will account for them as well, producing the correct results even if there are multiple zeros in the input array. In this video, we break down the approach step-by-step and explain how the solution works with optimal time and space efficiency.