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Remove Element (LeetCode 27) Explained in 5 Minutes

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May 9, 2026
4:30

In this video, we solve LeetCode 27 – “Remove Element” step by step. You’ll learn: * How to remove elements in-place without extra space * Two pointer technique explained clearly * Efficient approach (O(n) time, O(1) space) * Common mistakes to avoid Problem: Given an integer array nums and an integer val, remove all occurrences of val in-place and return the new length. The order of elements can be changed. It doesn't matter what you leave beyond the new length. --- ⏱ Time Complexity: O(n) 💾 Space Complexity: O(1) 💡 Key Concept: Use two pointers to overwrite unwanted elements and keep only valid ones. --- This is a common coding interview problem asked by companies like Amazon, Google, and Microsoft. --- 🔗 Connect with me: LinkedIn: https://www.linkedin.com/in/dashrat-rajpurohit/ X (Twitter): https://x.com/Dashrat_Singh_ GitHub: https://github.com/DashratRajpurohit --- If you're preparing for DSA or coding interviews, mastering in-place array manipulation is essential. #leetcode #removeelement #twopointers #codinginterview #dsa

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Remove Element (LeetCode 27) Explained in 5 Minutes | NatokHD