Robot Return to Origin | LeetCode 657 | C++ Solution with Explanation

In this video, we solve LeetCode Problem 657: Robot Return to Origin using a simple and intuitive approach that is perfect for beginners. We start by understanding the problem statement and how the robot moves on a 2D plane. Each move changes the robot’s position based on the direction given in the string. Then, we walk through examples step by step to see how the robot’s position changes after every move. After that, we implement a clean and efficient solution by tracking movements in all four directions and checking whether the robot returns to the starting point. 🧠 What You Will Learn in This Video: How to interpret movement-based problems Step-by-step dry run with sample input Tracking position using simple variables Clean and beginner-friendly C++ implementation Time and Space Complexity analysis 🧩 Problem Summary: You are given a string moves consisting of characters: U (Up) D (Down) L (Left) R (Right) Each move changes the robot’s position on a 2D plane. Your task is to determine whether the robot returns to the original position after performing all the moves. 💡 Approach Explained: We track the movement of the robot using counters: Increase count for U, decrease for D Increase count for R, decrease for L At the end: If both vertical and horizontal positions return to zero, the robot is back at the origin Otherwise, it is not ⏱️ Complexity Analysis: Time Complexity: O(n) Space Complexity: O(1) Where n is the length of the moves string. 💻 Topics Covered: Strings Simulation Basic counting technique Coordinate tracking 🚀 Why Watch This Video? This is a classic beginner problem that helps you understand how to simulate movements and track positions efficiently. It is very useful for building strong fundamentals in problem-solving and is commonly asked in coding interviews. #LeetCode657 #DSA #CodingForBeginners #LeetCodeEasy #Strings #Simulation #ProblemSolving #CodingInterview #LearnToCode #Cpp #Algorithms