Search a 2D Matrix - LeetCode 74

🔥 LeetCode 74: Search a 2D Matrix - C++ Solution Explained In this video, I solve LeetCode problem #74 - Search a 2D Matrix using C++ with an efficient binary search approach! ⏱️ Time Complexity: O(log(m*n)) 💾 Space Complexity: O(1) 📌 Problem Overview: You are given an m x n integer matrix with the following two properties: - Each row is sorted in non-decreasing order - The first integer of each row is greater than the last integer of the previous row Given an integer target, return true if target is in matrix or false otherwise. You must write a solution in O(log(m*n)) time complexity. Example: matrix = [[1,3,5,7],[10,11,16,20],[23,30,34,60]], target = 3 Output: true 💡 Solution Approach: - Treat the 2D matrix as a flattened 1D sorted array - Apply binary search on the virtual 1D array - Convert 1D index to 2D coordinates: row = mid / n, col = mid % n - Efficient single binary search achieves O(log(m*n)) complexity - Alternative: Two binary searches (first find row, then find column) 🔗 LeetCode Problem Link: https://leetcode.com/problems/search-a-2d-matrix/ 📚 Great problem combining binary search with 2D arrays - common interview pattern! ⭐ If this helped you, please like and subscribe for more coding solutions! #leetcode #cpp #dsa #coding #programming #binarysearch #2darray #matrix #algorithms #interview #faang #mediumleetcode