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simple calculator in python using if // very basic codes in python // from to very basic to complex

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Aug 13, 2018
10:47

source code by -Ak CSE_TECH'S - #simple calculator in python print("welcome-") print("1]addition") print("2]subtraction") print("3]multiplication") print("4]division") print("5]squre") print("6]cube") print("exit") x=input("enter your choice no : ") if(x=='1'): a=input("enter 1st no: ") b=input("enter 2nd no: ") c=(int(a)+int(b)) c=str(c) print("addition is: "+c) if(x=='2'): a=input("enter 1st no: ") b=input("enter 2nd no: ") c=(int(a)-int(b)) c=str(c) print("subtraction is: "+c) if(x=='3'): a=input("enter 1st no: ") b=input("enter 2nd no: ") c=(int(a)*int(b)) c=str(c) print("multiplication is: "+c) if(x=='4'): a=input("enter 1st no: ") b=input("enter 2nd no: ") c=(int(a) / int(b)) c=str(c) print("division is: "+c) if(x=='5'): a=input("enter 1st no: ") c=(int(a)*int(a)) c=str(c) print("addition is: "+c) if(x=='6'): a=input("enter 1st no: ") c=(int(a)*int(a)*int(a)) c=str(c) print("addition is: "+c) if(x=='exit'): print("thank you...")

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