Spherical Integration Example, Multivariable Calculus
We rewrite a triple integral written in rectangular (xyz) coordinates in spherical coordinates. This is a multi-step process: first we sketch the domain of integration, then we figure out the bounds for the spherical coordinates, then we perform the integration. (This integral would be simpler in polar/cylindrical coordinates, but the point of the exercise is really describing the domain with spherical coordinates.) Recall the coordinates: - Radius (π) Definition: In all examples, π represents the radial distance from the origin to a point. - Angle π Definition: π is defined as the angle from the positive π§-axis, analogous to latitude. - Angle π Definition: π represents the rotational angle in the π₯π¦-plane, analogous to longitude. Our computation begins with a visual exploration of the domain of integration in the π₯π¦-plane. This initial step is crucial, as it lays the foundation for our understanding of the problem in a three-dimensional context. We consider a triple integral whose limits are defined in rectangular coordinates, with a specific focus on the outer bounds, which represent a two-dimensional domain. The outer bounds suggest that the variable π¦ spans from βπ to π , creating a region confined within two horizontal lines. Next, the middle bounds dictate that π₯ is confined between 0 and sqrt(π ^2βπ¦^2. This limitation of π₯ to non-negative values, coupled with the equation π₯^2+π¦^2=π ^2, reveals that our domain is not an entire disk but rather the right semidisk of radius π in the π₯π¦-plane. Next, we visualize the π₯π¦-plane within the larger context of π₯π¦π§-space. Here, the third variable, π§, comes into play, ranging from the surface described by π§=sqrt(π₯2+π¦2) up to the plane π§=π . In essence, the domain we are dealing with is a solid half cone, originating from the right semicircle in the π₯π¦-plane and extending upward to the plane π§=π . Our task is to redefine the domain of integration in these spherical terms. Theta (π) Bounds: The domain extends from the negative to the positive y-axis, thus π ranges from βπ/2 to π/2. Phi (π) Bounds: The angle π starts from 0 (along the positive π§-axis) and opens down to the edge of the cone, which is determined to be π/4. Radius (π) Bounds: The radial distance π begins at 0 (at the origin) and extends to a maximum determined by the edge of the cone. This maximum distance varies with π, and is calculated as π /cos(π). Then we proceed in the video with the integration! Multivariable Calculus Unit 5 Lecture 5, supplement. #mathematics #multivariablecalculus #SphericalCoordinates #mathematicstutorials #tripleintegral #tripleintegration #matheducation #physicseducation #polarcoordinates #engineeringmath #iitjammathematics #calculus3
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