Valid Anagram | LeetCode Easy | Frequency Count Approach | C++

🔹 Problem: Valid Anagram (LeetCode) In this video, we solve one of the most popular string interview problems using frequency counting. The task is to determine whether two strings are anagrams of each other. --- 🔹 Brute Force Approach: One possible solution: - Sort both strings - Compare sorted strings This works but takes: O(n log n) time. --- 🔹 Optimized Frequency Count Approach: We use a frequency array. Steps: 1. Check string lengths 2. Count frequencies of characters in first string 3. Decrease frequencies using second string 4. If all frequencies become zero: - strings are anagrams --- 🔹 Key Idea: Anagrams always contain: - same characters - same frequencies --- 🔹 Dry Run Example: s = anagram t = nagaram Character frequencies match completely. Answer = true --- 🔹 Follow-Up (Unicode Characters): For Unicode inputs: - frequency array is not enough - unordered_map can be used instead --- 🔹 Time Complexity: O(n) 🔹 Space Complexity: O(1) --- 🔗 GitHub: https://github.com/DhruvOzha85 🔗 LeetCode Profile: https://leetcode.com/u/DhruvOzha/ 🔗 LinkedIn: https://www.linkedin.com/in/dhruv-ozha-bb378639b/ --- 📌 Notes: - Classic interview problem - Great for learning frequency counting - Important string manipulation concept --- 🔥 Follow for more daily DSA problem solutions! #leetcode #validanagram #strings #frequencycount #dsa #codinginterview #cplusplus #programming #algorithms #coding #leetcodeeasy #tech #softwareengineer #placements #codingpractice valid anagram, frequency counting, string manipulation, leetcode string problem, dsa problems, coding interview questions, c++ dsa, beginner dsa, algorithms, programming, interview prep, coding practice, data structures