00:00 - Understanding variable force
01:10 - Ques.1. A force f = 2 + x on a particle in X - direction where F is in newton and x in metres. Find the word done by this force during a displacement from x = 1.0 m to x = 2.0 m.
05:07 - Ques.2. A force f = -k / (x)^2 (x not equals to zero) acts on a particle in X - direction. find the work done by this force in this place in the particle from x = + a to x= + 2A. where k is a positive constant.
10:26 - Ques.3. An object is displaced from position vector r1 = (2i + 3j)m to r2 = (4i+6j)m under a force f = (3x^2 i+ 2 y j ) N .Find the work done by the force.
