LeetCode 1897 | Redistribute Characters to Make All Strings Equal | Python Frequency | AlgoYogi

Welcome to AlgoYogi! 🚀 Start Your Smart Coding Prep at 👉 https://algoyogi.io We solve LeetCode 1897: Redistribute Characters to Make All Strings Equal using a simple frequency divisibility check. Goal: After redistributing letters among all words, can every word become identical? Approach: - Count total frequency of each character across all words - Let n be the number of words - For every character c, require total_count[c] mod n equals 0 - If all characters satisfy this, return true, else false 👉 Problem Link: https://leetcode.com/problems/redistribute-characters-to-make-all-strings-equal/ --- ### ⏱ Timestamps 0:00 Introduction 0:20 Problem Statement 1:00 Frequency Divisibility Approach 7:00 Python Code Walkthrough 9:40 Time and Space Complexity --- ### 💡 Why Watch? - Clean O(total characters) solution with a single hash map - Crystal clear condition: each character count divisible by number of words - Interview friendly and easy to reason about #LeetCode #RedistributeCharacters #Python #AlgoYogi #HashMap #Counting