LeetCode 2490 | Circular Sentence | Python Word Chain Check | AlgoYogi
Welcome to AlgoYogi! π Start Your Smart Coding Prep at π https://algoyogi.io In this video, we solve **LeetCode 2490: Circular Sentence** using Python and a simple word chain check. A sentence is circular if the last letter of each word equals the first letter of the next word, and the last letter of the last word equals the first letter of the first word. Approach: - Split the sentence into words - For each adjacent pair (word[i], word[i+1]), check word[i][-1] == word[i+1][0] - Finally check last wordβs last char == first wordβs first char - Return True if all checks pass, else False π Problem Link: https://leetcode.com/problems/circular-sentence/description/ --- ### β± Timestamps 0:00 Introduction 0:20 Problem Statement 2:00 Word Chain Check Approach 3:40 Python Code Walkthrough 5:40 Time & Space Complexity --- ### π‘ Why Watch? - Clean O(n) check on words, no extra structures needed - Straightforward and ideal for string parsing practice - Handy pattern for chained constraints between words or letters #LeetCode #CircularSentence #Python #AlgoYogi #StringChain
Download
0 formatsNo download links available.