LeetCode #27 Remove Element 🔥 | Easy C++ Solution Explained Step-by-Step

🔥 LeetCode 27 - Remove Element | Easy C++ Solution 🚀 In this video, we solve the LeetCode problem "Remove Element" using an efficient in-place approach in C++ with a complete beginner-friendly explanation. 📌 Problem Statement: Given an integer array nums and a value val, remove all occurrences of val in-place and return the number of remaining elements. ━━━━━━━━━━━━━━━━━━━ ✅ Topics Covered: ✔️ Arrays ✔️ Two Pointer Technique ✔️ In-Place Array Modification ✔️ Beginner Friendly Explanation ✔️ Step-by-Step Dry Run ✔️ Time & Space Complexity Analysis ━━━━━━━━━━━━━━━━━━━ 💡 Approach Used: In this solution, we use a variable k to keep track of valid elements. * Traverse the array using a loop * If the current element is NOT equal to val 👉 place it at index k * Increment k * Finally, return k as the count of remaining elements This approach modifies the array in-place without using extra space. ━━━━━━━━━━━━━━━━━━━ 📌 Example: Input: nums = [3,2,2,3], val = 3 Output: k = 2 Updated nums: [2,2,*,*] ━━━━━━━━━━━━━━━━━━━ ⏱️ Time Complexity: O(n) 📦 Space Complexity: O(1) 👨‍💻 Language Used: C++ ━━━━━━━━━━━━━━━━━━━ 🔥 Perfect For: ✔️ Beginners in DSA ✔️ Array Practice Problems ✔️ Coding Interview Preparation ✔️ LeetCode Beginners ✔️ Placement Preparation 📢 In this video, you’ll learn: ✅ How in-place algorithms work ✅ How to remove elements efficiently ✅ How the two-pointer style approach works ✅ Easy C++ implementation with explanation ━━━━━━━━━━━━━━━━━━━ 👍 Like the video if you found it helpful 💬 Comment your doubts & suggestions 🔔 Subscribe for more LeetCode solutions and DSA tutorials #leetcode #removeelement #cpp #dsa #arrays #codinginterview #leetcodeeasy #cplusplustutorial #programming #twopointers