LeetCode 389 | Find the Difference | C++ Easy Solution Explained

In this video, I solve LeetCode Problem 389: "Find the Difference" using an optimized XOR Bit Manipulation approach in C++. We are given two strings where string `t` is created by shuffling string `s` and adding one extra character. The goal is to find that extra character efficiently. 🧠 Approach Used: We use the XOR operator because identical characters cancel each other out: 'a' ^ 'a' = 0 By XORing all characters from both strings, every matching character gets removed, and only the extra character remains. ✅ Time Complexity: O(n) ✅ Space Complexity: O(1) ⏱️ Timeline: 00:00 Introduction 00:20 Problem Statement 00:50 XOR Logic 01:40 C++ Code Explanation 02:40 Complexity Analysis & Conclusion 💻 Language: -- C++ (DSA) 🎯 Problem Link: https://leetcode.com/problems/find-the-difference/ 🌐 Connect With Me: 💼 LinkedIn : https://www.linkedin.com/in/harshitpandya2911/ 🐙 GitHub : https://github.com/harshitpandya-cg/LeetCode-Solutions/tree/main/0389-find-the-difference 💠Twitter/X : https://x.com/HarshitP68223 👍 Like, Share & Subscribe for more LeetCode and DSA solutions! #leetcode #leetcode389 #findthedifference #cpp #cplusplustutorial #cplusplus #dsa #datastructures #algorithms #coding #programming #codinginterview #technicalinterview #leetcodeeasy #bitmanipulation #xor #competitiveprogramming #softwareengineer #computerscience #developer #codingsolutions #leetcodeincpp #interviewpreparation #learncoding #dailycoding #codewithme #problemSolving #programmer #codingcommunity