LeetCode 7 Easy Explanation | Reverse Integer

🔥 LeetCode 7 - Reverse Integer | C++ Solution Explained In this video, I solve LeetCode Problem 7: "Reverse Integer" using an efficient mathematical approach in C++. The problem asks us to reverse the digits of a signed 32-bit integer while handling overflow conditions correctly. We will understand the logic step-by-step and implement an optimized solution with proper explanation. 🧠 Approach Used: We repeatedly extract the last digit of the number using the modulo (%) operator and build the reversed number. Example: 123 → 321 Before updating the reversed number, we check for integer overflow to ensure the result stays within the 32-bit signed integer range. ✅ Time Complexity: O(log n) ✅ Space Complexity: O(1) ⏱️ Timeline: 00:00 Introduction 00:20 Problem Statement 00:50 Mathematical Logic 01:40 C++ Code Explanation 02:40 Overflow Handling 03:00 Complexity Analysis & Conclusion 💻 Language: C++ 🎯 Problem Link: https://leetcode.com/problems/reverse-integer/ 🌐 Connect With Me: 💼 LinkedIn: https://www.linkedin.com/in/harshitpandya2911/ 🐙 GitHub: https://github.com/harshitpandya-cg/LeetCode-Solutions/tree/main/0007-reverse-integer 🧠 Twitter/X : https://x.com/HarshitP68223 👍 Like, Share & Subscribe for more LeetCode and DSA solutions! #leetcode #leetcode7 #reverseinteger #cpp #cplusplus #dsa #algorithms #codinginterview #programming #leetcodeeasy #competitiveprogramming #problemSolving #developer #coding