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Type 2 Improper Integrals (Conclusion)

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Nov 6, 2022
14:39

Two concluding Comprehensive type 2 improper integral problems worked out for your benefit with tips. *Please note for demonstration purposes (for the first question), the antiderivative was intentionally presented with the resubstituted "u" value, hence the original intervals (upper and lower limits) were retained for the definite integral procedure. A sort of modified procedure. However, the new lower interval limit would be "ln (0)" and the new upper interval limit would be "ln (2)", if, after the polynomial substitution technique, the "u" value is kept as antiderivative. The "ln (0)" lower limit is undefined! In both cases, the result would be the same regardless. Unique Integral Shortcut Video (hint): https://youtu.be/bh4SQY_VVdo The purpose of the channel is to learn, familiarize, and review the necessary precalculus and trigonometry/geometry topics that form a basis for calculus (with a focus on functions). Calculus topics include limits, derivatives, integrals, formula derivations, derivations/proofs, area/volumes of curves and calculus applications. Utilize simple and easy techniques to get the material across to you. Disclaimer: I am not a professor by profession. Thank you! #calculusfundamentals #calculus #functions #continuity #intervals #continuityofafunction #integralcalculus #integrationoflimits #definiteintegrals #definiteintegration #improperintegrals #infinity #professorcalculish #antiderivatives #integrals #domain #calculusapplications #limitconcept #limits #limitsandcalculus #indefiniteintegral #infinitediscontinuity #asymptotes #verticalasymptotes #polynomialintegration #polynomialsubstitutiontechnique

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