What is Memory Segmentation in 8086 Microprocessor || Ekeeda.com

"Memory Segmentation Segmentation in 8086 :- The size of address bus of 8086 is 20 and is able to address 1 Mbytes ( ) of physical memory. The compete 1 Mbytes memory can be divided into 16 segments, each of 64 Kbytes size. The addresses of the segment may be assigned as 0000H to F000H respectively. The offset values are from 0000H to FFFFFH. *8086 has a 20-bit address bus *So it can address a maximum of 1MB of memory *Physical available memory is divided into a number of logical segments. *8086 can work with only four 64KB segments at a time within this 1MB memory range. *These four memory segments are called Code Segment:- Code segment (CS) is a 16-bit register containing address of 64 KB segment with processor instructions. The processor uses CS segment for all accesses to instructions referenced by instruction pointer (IP) register. CS register cannot be changed directly. Stack Segment A section of memory set aside to store address and data while a subprogram executes Data Segment and Extra Segment Used for storing data value to be used in the program #OnlineLectures #EducationForFree #FullHD #HappyLearning #Engineering Thanks For Supporting Us Website - http://ekeeda.com Parent Channel - https://www.youtube.com/c/ekeeda Facebook - https://www.facebook.com/ekeeda.video Twitter - https://twitter.com/Ekeeda_Official Blogger - http://ekeeda.blogspot.in Pinterest - https://in.pinterest.com/ekeedavideo Digg - http://digg.com/u/ekeeda_Video Tumbler - https://www.tumblr.com/blog/ekeedavideo Reddit - https://www.reddit.com/user/ekeeda_Video LinkedIn- https://www.linkedin.com/in/ekeeda-video-4a5b83124 Happy Learning : ) -~-~~-~~~-~~-~- Please watch: "19 Problem 6 on SFD and BMD for the beam as shown in figure" https://www.youtube.com/watch?v=aQTRebqlvMw -~-~~-~~~-~~-~-